(3x^3-10x^2+13x-10)/(x-2)

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Solution for (3x^3-10x^2+13x-10)/(x-2) equation:


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(3*x^3-(10*x^2)+13*x-10)/(x-2) = 0

(3*x^3-10*x^2+13*x-10)/(x-2) = 0

3*x^3-10*x^2+13*x-10 = 0

3*x^3-10*x^2+13*x-10 = 0

{ 1, -1, 2, -2, 5, -5, 10, -10 }

1

x = 1

3*x^3-10*x^2+13*x-10 = -4

1

-1

x = -1

3*x^3-10*x^2+13*x-10 = -36

-1

2

x = 2

3*x^3-10*x^2+13*x-10 = 0

2

x-2

3*x^2-4*x+5

3*x^3-10*x^2+13*x-10

x-2

6*x^2-3*x^3

13*x-4*x^2-10

4*x^2-8*x

5*x-10

10-5*x

0

3*x^2-4*x+5 = 0

DELTA = (-4)^2-(3*4*5)

DELTA = -44

DELTA < 0

x in { 2}

x-2 = 0

1 = 0

x belongs to the empty set

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